Base | Representation |
---|---|
bin | 101101011011101100111… |
… | …110011000101111010011 |
3 | 102001110202001102101112021 |
4 | 231123230332120233103 |
5 | 402123101220043011 |
6 | 10350141050312311 |
7 | 441365044263652 |
oct | 55335476305723 |
9 | 12043661371467 |
10 | 3122122034131 |
11 | aa40a2549511 |
12 | 425108428697 |
13 | 19855154b369 |
14 | ab17bdc3199 |
15 | 56330b65471 |
hex | 2d6ecf98bd3 |
3122122034131 has 2 divisors, whose sum is σ = 3122122034132. Its totient is φ = 3122122034130.
The previous prime is 3122122034081. The next prime is 3122122034149. The reversal of 3122122034131 is 1314302212213.
It is a strong prime.
It is an emirp because it is prime and its reverse (1314302212213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3122122034131 - 221 = 3122119936979 is a prime.
It is a super-2 number, since 2×31221220341312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3122122034096 and 3122122034105.
It is not a weakly prime, because it can be changed into another prime (3122122034431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561061017065 + 1561061017066.
It is an arithmetic number, because the mean of its divisors is an integer number (1561061017066).
Almost surely, 23122122034131 is an apocalyptic number.
3122122034131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3122122034131 is an equidigital number, since it uses as much as digits as its factorization.
3122122034131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 3122122034131 its reverse (1314302212213), we get a palindrome (4436424246344).
The spelling of 3122122034131 in words is "three trillion, one hundred twenty-two billion, one hundred twenty-two million, thirty-four thousand, one hundred thirty-one".
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