Base | Representation |
---|---|
bin | 1110001100101101011011… |
… | …10011001001011100010011 |
3 | 11002112220002212022122222021 |
4 | 13012112231303021130103 |
5 | 13043024232441003021 |
6 | 150223355143552311 |
7 | 6401534603511655 |
oct | 706265563113423 |
9 | 132486085278867 |
10 | 31223033141011 |
11 | 9a48683252978 |
12 | 360329675b697 |
13 | 145641c91a97a |
14 | 79d2ba94c6d5 |
15 | 3922b1b6dc41 |
hex | 1c65adcc9713 |
31223033141011 has 2 divisors, whose sum is σ = 31223033141012. Its totient is φ = 31223033141010.
The previous prime is 31223033140993. The next prime is 31223033141021. The reversal of 31223033141011 is 11014133032213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31223033141011 - 227 = 31222898923283 is a prime.
It is a super-2 number, since 2×312230331410112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31223033141021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15611516570505 + 15611516570506.
It is an arithmetic number, because the mean of its divisors is an integer number (15611516570506).
Almost surely, 231223033141011 is an apocalyptic number.
31223033141011 is a deficient number, since it is larger than the sum of its proper divisors (1).
31223033141011 is an equidigital number, since it uses as much as digits as its factorization.
31223033141011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 31223033141011 its reverse (11014133032213), we get a palindrome (42237166173224).
The spelling of 31223033141011 in words is "thirty-one trillion, two hundred twenty-three billion, thirty-three million, one hundred forty-one thousand, eleven".
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