Base | Representation |
---|---|
bin | 100011011111110001101000… |
… | …0000100101001111010101011 |
3 | 1111221111221022202011212100220 |
4 | 1012333203100010221322223 |
5 | 311411040411424244321 |
6 | 3024020403030301123 |
7 | 122523622131366231 |
oct | 10677432004517253 |
9 | 1457457282155326 |
10 | 312230433431211 |
11 | 90539201928869 |
12 | 2b0284244b77a3 |
13 | 1052b285223c19 |
14 | 5716068328951 |
15 | 2616c6b8e69c6 |
hex | 11bf8d0129eab |
312230433431211 has 8 divisors (see below), whose sum is σ = 419101252928400. Its totient is φ = 206756618110752.
The previous prime is 312230433431183. The next prime is 312230433431227. The reversal of 312230433431211 is 112134334032213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 312230433431211 - 27 = 312230433431083 is a prime.
It is not an unprimeable number, because it can be changed into a prime (312230433431011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 349251043660 + ... + 349251044553.
It is an arithmetic number, because the mean of its divisors is an integer number (52387656616050).
Almost surely, 2312230433431211 is an apocalyptic number.
312230433431211 is a deficient number, since it is larger than the sum of its proper divisors (106870819497189).
312230433431211 is a wasteful number, since it uses less digits than its factorization.
312230433431211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 698502088365.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 312230433431211 its reverse (112134334032213), we get a palindrome (424364767463424).
The spelling of 312230433431211 in words is "three hundred twelve trillion, two hundred thirty billion, four hundred thirty-three million, four hundred thirty-one thousand, two hundred eleven".
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