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312234001004017 is a prime number
BaseRepresentation
bin100011011111110011010010…
…0101101110111010111110001
31111221112021112101012100020001
41012333212210231313113301
5311411120213224112032
63024022153031550001
7122524106421303151
oct10677464455672761
91457467471170201
10312234001004017
119053a772709044
122b02905b22b301
131052b70338c351
1457162c6076761
152616dc9c003e7
hex11bf9a4b775f1

312234001004017 has 2 divisors, whose sum is σ = 312234001004018. Its totient is φ = 312234001004016.

The previous prime is 312234001003993. The next prime is 312234001004071. The reversal of 312234001004017 is 710400100432213.

Together with next prime (312234001004071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 194563553548816 + 117670447455201 = 13948604^2 + 10847601^2 .

It is a cyclic number.

It is not a de Polignac number, because 312234001004017 - 27 = 312234001003889 is a prime.

It is not a weakly prime, because it can be changed into another prime (312234001004117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156117000502008 + 156117000502009.

It is an arithmetic number, because the mean of its divisors is an integer number (156117000502009).

Almost surely, 2312234001004017 is an apocalyptic number.

It is an amenable number.

312234001004017 is a deficient number, since it is larger than the sum of its proper divisors (1).

312234001004017 is an equidigital number, since it uses as much as digits as its factorization.

312234001004017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 28.

The spelling of 312234001004017 in words is "three hundred twelve trillion, two hundred thirty-four billion, one million, four thousand, seventeen".