Base | Representation |
---|---|
bin | 100011011111110011010010… |
… | …0101111001001011001101011 |
3 | 1111221112021112101211102010021 |
4 | 1012333212210233021121223 |
5 | 311411120213320340021 |
6 | 3024022153043101311 |
7 | 122524106424202552 |
oct | 10677464457113153 |
9 | 1457467471742107 |
10 | 312234001340011 |
11 | 9053a772918523 |
12 | 2b02905b371837 |
13 | 1052b70347926a |
14 | 57162c6122d99 |
15 | 2616dc9c69c41 |
hex | 11bf9a4bc966b |
312234001340011 has 2 divisors, whose sum is σ = 312234001340012. Its totient is φ = 312234001340010.
The previous prime is 312234001339999. The next prime is 312234001340171. The reversal of 312234001340011 is 110043100432213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312234001340011 - 215 = 312234001307243 is a prime.
It is not a weakly prime, because it can be changed into another prime (312234001940011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156117000670005 + 156117000670006.
It is an arithmetic number, because the mean of its divisors is an integer number (156117000670006).
Almost surely, 2312234001340011 is an apocalyptic number.
312234001340011 is a deficient number, since it is larger than the sum of its proper divisors (1).
312234001340011 is an equidigital number, since it uses as much as digits as its factorization.
312234001340011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 312234001340011 its reverse (110043100432213), we get a palindrome (422277101772224).
The spelling of 312234001340011 in words is "three hundred twelve trillion, two hundred thirty-four billion, one million, three hundred forty thousand, eleven".
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