Base | Representation |
---|---|
bin | 100011011111110011011110… |
… | …1101110010100001011010011 |
3 | 1111221112022121121122121102011 |
4 | 1012333212331232110023103 |
5 | 311411122043130134103 |
6 | 3024022302420203351 |
7 | 122524123004353246 |
oct | 10677467556241323 |
9 | 1457468547577364 |
10 | 312234420552403 |
11 | 9053a968515a48 |
12 | 2b029157839557 |
13 | 1052b76c28662b |
14 | 5716325a8925d |
15 | 2616e01975d6d |
hex | 11bf9bdb942d3 |
312234420552403 has 2 divisors, whose sum is σ = 312234420552404. Its totient is φ = 312234420552402.
The previous prime is 312234420552337. The next prime is 312234420552409. The reversal of 312234420552403 is 304255024432213.
It is a strong prime.
It is an emirp because it is prime and its reverse (304255024432213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312234420552403 - 221 = 312234418455251 is a prime.
It is not a weakly prime, because it can be changed into another prime (312234420552409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156117210276201 + 156117210276202.
It is an arithmetic number, because the mean of its divisors is an integer number (156117210276202).
Almost surely, 2312234420552403 is an apocalyptic number.
312234420552403 is a deficient number, since it is larger than the sum of its proper divisors (1).
312234420552403 is an equidigital number, since it uses as much as digits as its factorization.
312234420552403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 312234420552403 its reverse (304255024432213), we get a palindrome (616489444984616).
The spelling of 312234420552403 in words is "three hundred twelve trillion, two hundred thirty-four billion, four hundred twenty million, five hundred fifty-two thousand, four hundred three".
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