Base | Representation |
---|---|
bin | 1110001100111010111110… |
… | …00001000001100001101011 |
3 | 11002120120212101200001202021 |
4 | 13012131133001001201223 |
5 | 13043134124114010011 |
6 | 150231000302045311 |
7 | 6402212660120104 |
oct | 706353701014153 |
9 | 132516771601667 |
10 | 31230301313131 |
11 | 9a50772a12198 |
12 | 3604784879837 |
13 | 145700a65972b |
14 | 79d7a9d553ab |
15 | 392589cab471 |
hex | 1c675f04186b |
31230301313131 has 2 divisors, whose sum is σ = 31230301313132. Its totient is φ = 31230301313130.
The previous prime is 31230301313047. The next prime is 31230301313143. The reversal of 31230301313131 is 13131310303213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31230301313131 - 29 = 31230301312619 is a prime.
It is a super-2 number, since 2×312303013131312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31230301313096 and 31230301313105.
It is not a weakly prime, because it can be changed into another prime (31230301323131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615150656565 + 15615150656566.
It is an arithmetic number, because the mean of its divisors is an integer number (15615150656566).
Almost surely, 231230301313131 is an apocalyptic number.
31230301313131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31230301313131 is an equidigital number, since it uses as much as digits as its factorization.
31230301313131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 31230301313131 its reverse (13131310303213), we get a palindrome (44361611616344).
The spelling of 31230301313131 in words is "thirty-one trillion, two hundred thirty billion, three hundred one million, three hundred thirteen thousand, one hundred thirty-one".
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