Base | Representation |
---|---|
bin | 100011100000010111010010… |
… | …0111000100001101010111001 |
3 | 1111221210200002101202100000222 |
4 | 1013000232210320201222321 |
5 | 311413402032140210131 |
6 | 3024121500412505425 |
7 | 122532514325226545 |
oct | 10700564470415271 |
9 | 1457720071670028 |
10 | 312311313210041 |
11 | 9056a536405792 |
12 | 2b040036a7b275 |
13 | 10535aa46c2412 |
14 | 5719d3bc78a25 |
15 | 2618e0224a87b |
hex | 11c0ba4e21ab9 |
312311313210041 has 2 divisors, whose sum is σ = 312311313210042. Its totient is φ = 312311313210040.
The previous prime is 312311313210007. The next prime is 312311313210079. The reversal of 312311313210041 is 140012313113213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 175118349766441 + 137192963443600 = 13233229^2 + 11712940^2 .
It is a cyclic number.
It is not a de Polignac number, because 312311313210041 - 222 = 312311309015737 is a prime.
It is not a weakly prime, because it can be changed into another prime (312311313218041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156155656605020 + 156155656605021.
It is an arithmetic number, because the mean of its divisors is an integer number (156155656605021).
Almost surely, 2312311313210041 is an apocalyptic number.
It is an amenable number.
312311313210041 is a deficient number, since it is larger than the sum of its proper divisors (1).
312311313210041 is an equidigital number, since it uses as much as digits as its factorization.
312311313210041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 312311313210041 its reverse (140012313113213), we get a palindrome (452323626323254).
The spelling of 312311313210041 in words is "three hundred twelve trillion, three hundred eleven billion, three hundred thirteen million, two hundred ten thousand, forty-one".
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