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31231301210017 is a prime number
BaseRepresentation
bin1110001100111100110101…
…00111010100111110100001
311002120200110002011002102021
413012132122213110332201
513043143201102210032
6150231243421221441
76402246521111266
oct706363247247641
9132520402132367
1031231301210017
119a51136375557
123604a03701881
13145713985b9ac
1479d862a7726d
153925e796c097
hex1c679a9d4fa1

31231301210017 has 2 divisors, whose sum is σ = 31231301210018. Its totient is φ = 31231301210016.

The previous prime is 31231301209973. The next prime is 31231301210033. The reversal of 31231301210017 is 71001210313213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30205312516096 + 1025988693921 = 5495936^2 + 1012911^2 .

It is a cyclic number.

It is not a de Polignac number, because 31231301210017 - 219 = 31231300685729 is a prime.

It is a super-2 number, since 2×312313012100172 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31231301209973 and 31231301210000.

It is not a weakly prime, because it can be changed into another prime (31231301210617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615650605008 + 15615650605009.

It is an arithmetic number, because the mean of its divisors is an integer number (15615650605009).

Almost surely, 231231301210017 is an apocalyptic number.

It is an amenable number.

31231301210017 is a deficient number, since it is larger than the sum of its proper divisors (1).

31231301210017 is an equidigital number, since it uses as much as digits as its factorization.

31231301210017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

The spelling of 31231301210017 in words is "thirty-one trillion, two hundred thirty-one billion, three hundred one million, two hundred ten thousand, seventeen".