Base | Representation |
---|---|
bin | 1110001100111101000001… |
… | …01111100011110011000011 |
3 | 11002120200201020121221112011 |
4 | 13012132200233203303003 |
5 | 13043143403412444141 |
6 | 150231301533113351 |
7 | 6402252210063361 |
oct | 706364057436303 |
9 | 132520636557464 |
10 | 31231404031171 |
11 | 9a51189413613 |
12 | 3604a32028857 |
13 | 1457154c4c606 |
14 | 79d8725a0631 |
15 | 3926019cc881 |
hex | 1c67a0be3cc3 |
31231404031171 has 2 divisors, whose sum is σ = 31231404031172. Its totient is φ = 31231404031170.
The previous prime is 31231404031133. The next prime is 31231404031189. The reversal of 31231404031171 is 17113040413213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31231404031171 is a prime.
It is not a weakly prime, because it can be changed into another prime (31231404031571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615702015585 + 15615702015586.
It is an arithmetic number, because the mean of its divisors is an integer number (15615702015586).
Almost surely, 231231404031171 is an apocalyptic number.
31231404031171 is a deficient number, since it is larger than the sum of its proper divisors (1).
31231404031171 is an equidigital number, since it uses as much as digits as its factorization.
31231404031171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 31231404031171 its reverse (17113040413213), we get a palindrome (48344444444384).
The spelling of 31231404031171 in words is "thirty-one trillion, two hundred thirty-one billion, four hundred four million, thirty-one thousand, one hundred seventy-one".
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