Base | Representation |
---|---|
bin | 100011100000100001011100… |
… | …1010101010010110011100011 |
3 | 1111221212202101221000121120111 |
4 | 1013001002321111102303203 |
5 | 311414231223032212011 |
6 | 3024135505402352151 |
7 | 122534216103424054 |
oct | 10701027125226343 |
9 | 1457782357017514 |
10 | 312333131132131 |
11 | 9057881201a55a |
12 | 2b0443057bb657 |
13 | 10537b708c37a5 |
14 | 571b00b78072b |
15 | 261977c8b0121 |
hex | 11c10b9552ce3 |
312333131132131 has 2 divisors, whose sum is σ = 312333131132132. Its totient is φ = 312333131132130.
The previous prime is 312333131132119. The next prime is 312333131132137. The reversal of 312333131132131 is 131231131333213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312333131132131 is a prime.
It is a super-2 number, since 2×3123331311321312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312333131132093 and 312333131132102.
It is not a weakly prime, because it can be changed into another prime (312333131132137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156166565566065 + 156166565566066.
It is an arithmetic number, because the mean of its divisors is an integer number (156166565566066).
Almost surely, 2312333131132131 is an apocalyptic number.
312333131132131 is a deficient number, since it is larger than the sum of its proper divisors (1).
312333131132131 is an equidigital number, since it uses as much as digits as its factorization.
312333131132131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8748, while the sum is 31.
Adding to 312333131132131 its reverse (131231131333213), we get a palindrome (443564262465344).
The spelling of 312333131132131 in words is "three hundred twelve trillion, three hundred thirty-three billion, one hundred thirty-one million, one hundred thirty-two thousand, one hundred thirty-one".
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