312334013041 has 4 divisors (see below), whose sum is σ = 313338302784. Its totient is φ = 311329723300.

The previous prime is 312334013039. The next prime is 312334013059. The reversal of 312334013041 is 140310433213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 140310433213 = 941 ⋅149107793.

It is a cyclic number.

It is not a de Polignac number, because 312334013041 - 2¹ = 312334013039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312334012997 and 312334013015.

It is not an unprimeable number, because it can be changed into a prime (312334013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502144405 + ... + 502145026.

It is an arithmetic number, because the mean of its divisors is an integer number (78334575696).

Almost surely, 2^312334013041 is an apocalyptic number.

It is an amenable number.

312334013041 is a deficient number, since it is larger than the sum of its proper divisors (1004289743).

312334013041 is a wasteful number, since it uses less digits than its factorization.

312334013041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1004289742.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 312334013041 its reverse (140310433213), we get a palindrome (452644446254).

The spelling of 312334013041 in words is "three hundred twelve billion, three hundred thirty-four million, thirteen thousand, forty-one".