Base | Representation |
---|---|
bin | 101101011100111100001… |
… | …101001100001101100011 |
3 | 102001121011200200212010122 |
4 | 231130330031030031203 |
5 | 402133312014040133 |
6 | 10350521013350455 |
7 | 441443015056343 |
oct | 55347415141543 |
9 | 12047150625118 |
10 | 3123451315043 |
11 | aa4714925984 |
12 | 42541963842b |
13 | 198703a68c07 |
14 | ab266766d23 |
15 | 563ac6db498 |
hex | 2d73c34c363 |
3123451315043 has 2 divisors, whose sum is σ = 3123451315044. Its totient is φ = 3123451315042.
The previous prime is 3123451315013. The next prime is 3123451315079. The reversal of 3123451315043 is 3405131543213.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3123451315043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3123451314994 and 3123451315012.
It is not a weakly prime, because it can be changed into another prime (3123451315003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561725657521 + 1561725657522.
It is an arithmetic number, because the mean of its divisors is an integer number (1561725657522).
Almost surely, 23123451315043 is an apocalyptic number.
3123451315043 is a deficient number, since it is larger than the sum of its proper divisors (1).
3123451315043 is an equidigital number, since it uses as much as digits as its factorization.
3123451315043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 3123451315043 its reverse (3405131543213), we get a palindrome (6528582858256).
The spelling of 3123451315043 in words is "three trillion, one hundred twenty-three billion, four hundred fifty-one million, three hundred fifteen thousand, forty-three".
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