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312404131102177 is a prime number
BaseRepresentation
bin100011100001000010100000…
…1010000101011110111100001
31111222010112200000222210110201
41013002011001100223313201
5311421412130030232202
63024232250534225201
7122542311412261222
oct10702050120536741
91458115600883421
10312404131102177
11905a5936714954
122b05601b4b5201
131054177726779a
1457206250d7249
15261b535b98387
hex11c214142bde1

312404131102177 has 2 divisors, whose sum is σ = 312404131102178. Its totient is φ = 312404131102176.

The previous prime is 312404131102171. The next prime is 312404131102201. The reversal of 312404131102177 is 771201131404213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 255741537270241 + 56662593831936 = 15991921^2 + 7527456^2 .

It is an emirp because it is prime and its reverse (771201131404213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312404131102177 - 215 = 312404131069409 is a prime.

It is a super-2 number, since 2×3124041311021772 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (312404131102171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156202065551088 + 156202065551089.

It is an arithmetic number, because the mean of its divisors is an integer number (156202065551089).

Almost surely, 2312404131102177 is an apocalyptic number.

It is an amenable number.

312404131102177 is a deficient number, since it is larger than the sum of its proper divisors (1).

312404131102177 is an equidigital number, since it uses as much as digits as its factorization.

312404131102177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28224, while the sum is 37.

The spelling of 312404131102177 in words is "three hundred twelve trillion, four hundred four billion, one hundred thirty-one million, one hundred two thousand, one hundred seventy-seven".