312413143431313 has 4 divisors (see below), whose sum is σ = 312753092445760. Its totient is φ = 312073194416868.

The previous prime is 312413143431293. The next prime is 312413143431349. The reversal of 312413143431313 is 313134341314213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-312413143431313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312413143431383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169974505845 + ... + 169974507682.

It is an arithmetic number, because the mean of its divisors is an integer number (78188273111440).

Almost surely, 2^{312413143431313} is an apocalyptic number.

It is an amenable number.

312413143431313 is a deficient number, since it is larger than the sum of its proper divisors (339949014447).

312413143431313 is an equidigital number, since it uses as much as digits as its factorization.

312413143431313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339949014446.

The product of its digits is 93312, while the sum is 37.

Adding to 312413143431313 its reverse (313134341314213), we get a palindrome (625547484745526).

The spelling of 312413143431313 in words is "three hundred twelve trillion, four hundred thirteen billion, one hundred forty-three million, four hundred thirty-one thousand, three hundred thirteen".