Base | Representation |
---|---|
bin | 11101000110001000… |
… | …001101110101100001 |
3 | 2222122021002000000221 |
4 | 131012020031311201 |
5 | 1002440240030032 |
6 | 22204014043041 |
7 | 2154121631542 |
oct | 350610156541 |
9 | 88567060027 |
10 | 31241330017 |
11 | 12281a09707 |
12 | 607a7a9481 |
13 | 2c3b5ca5c1 |
14 | 17252564c9 |
15 | c2caca597 |
hex | 74620dd61 |
31241330017 has 2 divisors, whose sum is σ = 31241330018. Its totient is φ = 31241330016.
The previous prime is 31241329997. The next prime is 31241330023. The reversal of 31241330017 is 71003314213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26088387361 + 5152942656 = 161519^2 + 71784^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31241330017 is a prime.
It is a super-2 number, since 2×312413300172 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31241329973 and 31241330000.
It is not a weakly prime, because it can be changed into another prime (31241334017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15620665008 + 15620665009.
It is an arithmetic number, because the mean of its divisors is an integer number (15620665009).
Almost surely, 231241330017 is an apocalyptic number.
It is an amenable number.
31241330017 is a deficient number, since it is larger than the sum of its proper divisors (1).
31241330017 is an equidigital number, since it uses as much as digits as its factorization.
31241330017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 31241330017 in words is "thirty-one billion, two hundred forty-one million, three hundred thirty thousand, seventeen".
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