Base | Representation |
---|---|
bin | 1001000101111100001… |
… | …00101101001100101001 |
3 | 1002212102112200011202211 |
4 | 10202332010231030221 |
5 | 20104322144100212 |
6 | 355305441125121 |
7 | 31400135600266 |
oct | 4427604551451 |
9 | 1085375604684 |
10 | 312426550057 |
11 | 110554708286 |
12 | 506730297a1 |
13 | 2360046c5cb |
14 | 1119b67626d |
15 | 81d85d99a7 |
hex | 48be12d329 |
312426550057 has 2 divisors, whose sum is σ = 312426550058. Its totient is φ = 312426550056.
The previous prime is 312426550039. The next prime is 312426550109. The reversal of 312426550057 is 750055624213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 240089220121 + 72337329936 = 489989^2 + 268956^2 .
It is a cyclic number.
It is not a de Polignac number, because 312426550057 - 215 = 312426517289 is a prime.
It is a super-2 number, since 2×3124265500572 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312426550757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156213275028 + 156213275029.
It is an arithmetic number, because the mean of its divisors is an integer number (156213275029).
Almost surely, 2312426550057 is an apocalyptic number.
It is an amenable number.
312426550057 is a deficient number, since it is larger than the sum of its proper divisors (1).
312426550057 is an equidigital number, since it uses as much as digits as its factorization.
312426550057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 312426550057 in words is "three hundred twelve billion, four hundred twenty-six million, five hundred fifty thousand, fifty-seven".
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