Base | Representation |
---|---|
bin | 101101011101101111011… |
… | …001010100110110011011 |
3 | 102001200101112201101111111 |
4 | 231131233121110312123 |
5 | 402142041343243141 |
6 | 10351142133041151 |
7 | 441503213651242 |
oct | 55355731246633 |
9 | 12050345641444 |
10 | 3124310134171 |
11 | aa5015690456 |
12 | 4256191861b7 |
13 | 19880c974405 |
14 | ab308843959 |
15 | 5640ccd1381 |
hex | 2d76f654d9b |
3124310134171 has 2 divisors, whose sum is σ = 3124310134172. Its totient is φ = 3124310134170.
The previous prime is 3124310134151. The next prime is 3124310134223. The reversal of 3124310134171 is 1714310134213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3124310134171 - 211 = 3124310132123 is a prime.
It is a super-2 number, since 2×31243101341712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3124310134151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562155067085 + 1562155067086.
It is an arithmetic number, because the mean of its divisors is an integer number (1562155067086).
Almost surely, 23124310134171 is an apocalyptic number.
3124310134171 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124310134171 is an equidigital number, since it uses as much as digits as its factorization.
3124310134171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 3124310134171 its reverse (1714310134213), we get a palindrome (4838620268384).
The spelling of 3124310134171 in words is "three trillion, one hundred twenty-four billion, three hundred ten million, one hundred thirty-four thousand, one hundred seventy-one".
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