Base | Representation |
---|---|
bin | 101101011101110000100… |
… | …101000110111011111011 |
3 | 102001200102221002200110111 |
4 | 231131300211012323323 |
5 | 402142111440000443 |
6 | 10351144122525151 |
7 | 441503544551413 |
oct | 55356045067373 |
9 | 12050387080414 |
10 | 3124330000123 |
11 | aa5025919aa2 |
12 | 4256239667b7 |
13 | 198813b0b807 |
14 | ab30b335643 |
15 | 5640e90769d |
hex | 2d770946efb |
3124330000123 has 2 divisors, whose sum is σ = 3124330000124. Its totient is φ = 3124330000122.
The previous prime is 3124330000109. The next prime is 3124330000139. The reversal of 3124330000123 is 3210000334213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3124330000123 - 29 = 3124329999611 is a prime.
It is a super-2 number, since 2×31243300001232 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3124330000094 and 3124330000103.
It is not a weakly prime, because it can be changed into another prime (3124330000823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562165000061 + 1562165000062.
It is an arithmetic number, because the mean of its divisors is an integer number (1562165000062).
Almost surely, 23124330000123 is an apocalyptic number.
3124330000123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3124330000123 is an equidigital number, since it uses as much as digits as its factorization.
3124330000123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3124330000123 its reverse (3210000334213), we get a palindrome (6334330334336).
The spelling of 3124330000123 in words is "three trillion, one hundred twenty-four billion, three hundred thirty million, one hundred twenty-three", and thus it is an aban number.
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