312521444125201 has 2 divisors, whose sum is σ = 312521444125202. Its totient is φ = 312521444125200.

The previous prime is 312521444125181. The next prime is 312521444125301. The reversal of 312521444125201 is 102521444125213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 249961633530625 + 62559810594576 = 15810175^2 + 7909476^2 .

It is a cyclic number.

It is not a de Polignac number, because 312521444125201 - 2¹¹ = 312521444123153 is a prime.

It is a super-4 number, since 4×312521444125201⁴ (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (312521444125301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156260722062600 + 156260722062601.

It is an arithmetic number, because the mean of its divisors is an integer number (156260722062601).

Almost surely, 2^{312521444125201} is an apocalyptic number.

It is an amenable number.

312521444125201 is a deficient number, since it is larger than the sum of its proper divisors (1).

312521444125201 is an equidigital number, since it uses as much as digits as its factorization.

312521444125201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76800, while the sum is 37.

The spelling of 312521444125201 in words is "three hundred twelve trillion, five hundred twenty-one billion, four hundred forty-four million, one hundred twenty-five thousand, two hundred one".