Base | Representation |
---|---|
bin | 1011101001001000… |
… | …0101101001011011 |
3 | 22001210210212222021 |
4 | 2322102011221123 |
5 | 22400034211044 |
6 | 1234042035311 |
7 | 140306434114 |
oct | 27222055133 |
9 | 8053725867 |
10 | 3125303899 |
11 | 1364175093 |
12 | 7327a8b37 |
13 | 3aa647663 |
14 | 21910320b |
15 | 134595e84 |
hex | ba485a5b |
3125303899 has 2 divisors, whose sum is σ = 3125303900. Its totient is φ = 3125303898.
The previous prime is 3125303891. The next prime is 3125303981. The reversal of 3125303899 is 9983035213.
3125303899 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (9983035213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3125303899 - 23 = 3125303891 is a prime.
It is a super-2 number, since 2×31253038992 = 19535048922209204402, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3125303891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562651949 + 1562651950.
It is an arithmetic number, because the mean of its divisors is an integer number (1562651950).
Almost surely, 23125303899 is an apocalyptic number.
3125303899 is a deficient number, since it is larger than the sum of its proper divisors (1).
3125303899 is an equidigital number, since it uses as much as digits as its factorization.
3125303899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 43.
The square root of 3125303899 is about 55904.4175267036. The cubic root of 3125303899 is about 1462.0562598938.
The spelling of 3125303899 in words is "three billion, one hundred twenty-five million, three hundred three thousand, eight hundred ninety-nine".
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