312531254114251 has 4 divisors (see below), whose sum is σ = 312543626225104. Its totient is φ = 312518882003400.

The previous prime is 312531254114243. The next prime is 312531254114257. The reversal of 312531254114251 is 152411452135213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 312531254114251 - 2³ = 312531254114243 is a prime.

It is a super-2 number, since 2×312531254114251² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312531254114257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6186017535 + ... + 6186068056.

It is an arithmetic number, because the mean of its divisors is an integer number (78135906556276).

Almost surely, 2^{312531254114251} is an apocalyptic number.

312531254114251 is a deficient number, since it is larger than the sum of its proper divisors (12372110853).

312531254114251 is a wasteful number, since it uses less digits than its factorization.

312531254114251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12372110852.

The product of its digits is 144000, while the sum is 40.

The spelling of 312531254114251 in words is "three hundred twelve trillion, five hundred thirty-one billion, two hundred fifty-four million, one hundred fourteen thousand, two hundred fifty-one".