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3125314420051 = 7726974044683
BaseRepresentation
bin101101011110101011010…
…000010111110101010011
3102001202222112110101201211
4231132223100113311103
5402201120442420201
610351425530240551
7441540130152355
oct55365320276523
912052875411654
103125314420051
11aa549057128a
12425859586157
1319893ca52305
14ab3a1d890d5
155646b05c651
hex2d7ab417d53

3125314420051 has 4 divisors (see below), whose sum is σ = 3125319237432. Its totient is φ = 3125309602672.

The previous prime is 3125314420043. The next prime is 3125314420061. The reversal of 3125314420051 is 1500244135213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3125314420051 - 23 = 3125314420043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3125314419995 and 3125314420022.

It is not an unprimeable number, because it can be changed into a prime (3125314420001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1249645 + ... + 2795038.

It is an arithmetic number, because the mean of its divisors is an integer number (781329809358).

Almost surely, 23125314420051 is an apocalyptic number.

3125314420051 is a deficient number, since it is larger than the sum of its proper divisors (4817381).

3125314420051 is an equidigital number, since it uses as much as digits as its factorization.

3125314420051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4817380.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 3125314420051 its reverse (1500244135213), we get a palindrome (4625558555264).

The spelling of 3125314420051 in words is "three trillion, one hundred twenty-five billion, three hundred fourteen million, four hundred twenty thousand, fifty-one".

Divisors: 1 772697 4044683 3125314420051