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31253200523483 is a prime number
BaseRepresentation
bin1110001101100101100111…
…11010100101000011011011
311002122202222021120110221012
413012302303322211003123
513044023023313222413
6150245304435404135
76403653305155241
oct706626372450333
9132582867513835
1031253200523483
119a5a453a20924
1236090b575364b
131459219889843
147a093d2c8791
15392e7a30c7a8
hex1c6cb3ea50db

31253200523483 has 2 divisors, whose sum is σ = 31253200523484. Its totient is φ = 31253200523482.

The previous prime is 31253200523429. The next prime is 31253200523603. The reversal of 31253200523483 is 38432500235213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 31253200523483 - 226 = 31253133414619 is a prime.

It is a super-2 number, since 2×312532005234832 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31253200523483.

It is not a weakly prime, because it can be changed into another prime (31253200523183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15626600261741 + 15626600261742.

It is an arithmetic number, because the mean of its divisors is an integer number (15626600261742).

Almost surely, 231253200523483 is an apocalyptic number.

31253200523483 is a deficient number, since it is larger than the sum of its proper divisors (1).

31253200523483 is an equidigital number, since it uses as much as digits as its factorization.

31253200523483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 31253200523483 its reverse (38432500235213), we get a palindrome (69685700758696).

The spelling of 31253200523483 in words is "thirty-one trillion, two hundred fifty-three billion, two hundred million, five hundred twenty-three thousand, four hundred eighty-three".