Base | Representation |
---|---|
bin | 1001000110010011110… |
… | …01111110010011011011 |
3 | 1002212221101012200111220 |
4 | 10203021321332103123 |
5 | 20110224004010011 |
6 | 355341252023123 |
7 | 31405066122513 |
oct | 4431171762333 |
9 | 1085841180456 |
10 | 312625063131 |
11 | 110646775077 |
12 | 50709601aa3 |
13 | 23632625b74 |
14 | 111b9b8c843 |
15 | 81eac4d506 |
hex | 48c9e7e4db |
312625063131 has 4 divisors (see below), whose sum is σ = 416833417512. Its totient is φ = 208416708752.
The previous prime is 312625063109. The next prime is 312625063133. The reversal of 312625063131 is 131360526213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312625063131 is a prime.
It is a super-2 number, since 2×3126250631312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312625063092 and 312625063101.
It is not an unprimeable number, because it can be changed into a prime (312625063133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52104177186 + ... + 52104177191.
It is an arithmetic number, because the mean of its divisors is an integer number (104208354378).
Almost surely, 2312625063131 is an apocalyptic number.
312625063131 is a deficient number, since it is larger than the sum of its proper divisors (104208354381).
312625063131 is a wasteful number, since it uses less digits than its factorization.
312625063131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104208354380.
The product of its (nonzero) digits is 19440, while the sum is 33.
Adding to 312625063131 its reverse (131360526213), we get a palindrome (443985589344).
The spelling of 312625063131 in words is "three hundred twelve billion, six hundred twenty-five million, sixty-three thousand, one hundred thirty-one".
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