Base | Representation |
---|---|
bin | 101101100011000011111… |
… | …010010000101010011011 |
3 | 102002020010200112010020101 |
4 | 231203003322100222123 |
5 | 402240241343134321 |
6 | 10353525052040231 |
7 | 442064613462502 |
oct | 55430372205233 |
9 | 12066120463211 |
10 | 3130023021211 |
11 | aa7487439aa9 |
12 | 426752463077 |
13 | 199210405048 |
14 | ab6cb475839 |
15 | 56644603791 |
hex | 2d8c3e90a9b |
3130023021211 has 2 divisors, whose sum is σ = 3130023021212. Its totient is φ = 3130023021210.
The previous prime is 3130023021179. The next prime is 3130023021241. The reversal of 3130023021211 is 1121203200313.
3130023021211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3130023021211 - 25 = 3130023021179 is a prime.
It is a super-2 number, since 2×31300230212112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3130023021241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565011510605 + 1565011510606.
It is an arithmetic number, because the mean of its divisors is an integer number (1565011510606).
Almost surely, 23130023021211 is an apocalyptic number.
3130023021211 is a deficient number, since it is larger than the sum of its proper divisors (1).
3130023021211 is an equidigital number, since it uses as much as digits as its factorization.
3130023021211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 3130023021211 its reverse (1121203200313), we get a palindrome (4251226221524).
The spelling of 3130023021211 in words is "three trillion, one hundred thirty billion, twenty-three million, twenty-one thousand, two hundred eleven".
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