Base | Representation |
---|---|
bin | 1110001110111111000101… |
… | …10000010011111011011011 |
3 | 11002211100221121101120001021 |
4 | 13013133202300103323123 |
5 | 13100314410114020212 |
6 | 150323330443303311 |
7 | 6410303453404651 |
oct | 707374260237333 |
9 | 132740847346037 |
10 | 31301231001307 |
11 | 9a788609737a3 |
12 | 361647ab1ab37 |
13 | 1460902593817 |
14 | 7a2db8214dd1 |
15 | 39433bd10307 |
hex | 1c77e2c13edb |
31301231001307 has 2 divisors, whose sum is σ = 31301231001308. Its totient is φ = 31301231001306.
The previous prime is 31301231001239. The next prime is 31301231001319. The reversal of 31301231001307 is 70310013210313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31301231001307 - 243 = 22505137979099 is a prime.
It is not a weakly prime, because it can be changed into another prime (31301231001347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15650615500653 + 15650615500654.
It is an arithmetic number, because the mean of its divisors is an integer number (15650615500654).
Almost surely, 231301231001307 is an apocalyptic number.
31301231001307 is a deficient number, since it is larger than the sum of its proper divisors (1).
31301231001307 is an equidigital number, since it uses as much as digits as its factorization.
31301231001307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 31301231001307 in words is "thirty-one trillion, three hundred one billion, two hundred thirty-one million, one thousand, three hundred seven".
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