Base | Representation |
---|---|
bin | 101101100011010000111… |
… | …001110010011100110001 |
3 | 102002020200212200122122201 |
4 | 231203100321302130301 |
5 | 402241213144020030 |
6 | 10354002440103201 |
7 | 442103201334040 |
oct | 55432071623461 |
9 | 12066625618581 |
10 | 3130241001265 |
11 | aa7589492704 |
12 | 4267b3464b01 |
13 | 199246616221 |
14 | ab70c3b8557 |
15 | 566588102ca |
hex | 2d8d0e72731 |
3130241001265 has 32 divisors (see below), whose sum is σ = 4394222680320. Its totient is φ = 2095824374784.
The previous prime is 3130241001233. The next prime is 3130241001271. The reversal of 3130241001265 is 5621001420313.
3130241001265 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3130241001265 - 25 = 3130241001233 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4118077 + ... + 4818613.
It is an arithmetic number, because the mean of its divisors is an integer number (137319458760).
Almost surely, 23130241001265 is an apocalyptic number.
3130241001265 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3130241001265 is a deficient number, since it is larger than the sum of its proper divisors (1263981679055).
3130241001265 is a wasteful number, since it uses less digits than its factorization.
3130241001265 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 703561.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 3130241001265 its reverse (5621001420313), we get a palindrome (8751242421578).
The spelling of 3130241001265 in words is "three trillion, one hundred thirty billion, two hundred forty-one million, one thousand, two hundred sixty-five".
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