Base | Representation |
---|---|
bin | 100011100101100111110111… |
… | …1100011010010101001010010 |
3 | 1112001100202210002002002010111 |
4 | 1013023033233203102221102 |
5 | 312012222334313043102 |
6 | 3025433520100151534 |
7 | 122635653215301214 |
oct | 10713175743225122 |
9 | 1461322702062114 |
10 | 313034120440402 |
11 | 9081903022a099 |
12 | 2b1381396985aa |
13 | 10588cb5cc622a |
14 | 5742d0a20c5b4 |
15 | 262cb08735cd7 |
hex | 11cb3ef8d2a52 |
313034120440402 has 4 divisors (see below), whose sum is σ = 469551180660606. Its totient is φ = 156517060220200.
The previous prime is 313034120440397. The next prime is 313034120440403. The reversal of 313034120440402 is 204044021430313.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 291678270545281 + 21355849895121 = 17078591^2 + 4621239^2 .
It is a super-2 number, since 2×3130341204404022 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (313034120440403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78258530110099 + ... + 78258530110102.
Almost surely, 2313034120440402 is an apocalyptic number.
313034120440402 is a deficient number, since it is larger than the sum of its proper divisors (156517060220204).
313034120440402 is a wasteful number, since it uses less digits than its factorization.
313034120440402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156517060220203.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 313034120440402 its reverse (204044021430313), we get a palindrome (517078141870715).
The spelling of 313034120440402 in words is "three hundred thirteen trillion, thirty-four billion, one hundred twenty million, four hundred forty thousand, four hundred two".
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