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313040033120041 is a prime number
BaseRepresentation
bin100011100101101010100111…
…1111110010111111100101001
31112001101100001010211022210021
41013023111033332113330221
5312012321441434320131
63025440334513320441
7122636252562244243
oct10713251776277451
91461340033738707
10313040033120041
1190820594839897
122b139309866121
1310589718c6a936
14574330b5ab093
15262cd52870e11
hex11cb54ff97f29

313040033120041 has 2 divisors, whose sum is σ = 313040033120042. Its totient is φ = 313040033120040.

The previous prime is 313040033120021. The next prime is 313040033120057. The reversal of 313040033120041 is 140021330040313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 302607908305641 + 10432124814400 = 17395629^2 + 3229880^2 .

It is a cyclic number.

It is not a de Polignac number, because 313040033120041 - 219 = 313040032595753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 313040033119988 and 313040033120015.

It is not a weakly prime, because it can be changed into another prime (313040033120021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156520016560020 + 156520016560021.

It is an arithmetic number, because the mean of its divisors is an integer number (156520016560021).

Almost surely, 2313040033120041 is an apocalyptic number.

It is an amenable number.

313040033120041 is a deficient number, since it is larger than the sum of its proper divisors (1).

313040033120041 is an equidigital number, since it uses as much as digits as its factorization.

313040033120041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 313040033120041 its reverse (140021330040313), we get a palindrome (453061363160354).

The spelling of 313040033120041 in words is "three hundred thirteen trillion, forty billion, thirty-three million, one hundred twenty thousand, forty-one".