Base | Representation |
---|---|
bin | 11101001001111111… |
… | …101110101110100111 |
3 | 2222210210011110112221 |
4 | 131021333232232213 |
5 | 1003103342324221 |
6 | 22214252453211 |
7 | 2155540300561 |
oct | 351177565647 |
9 | 88723143487 |
10 | 31306214311 |
11 | 123055a6199 |
12 | 609847a207 |
13 | 2c4bb97788 |
14 | 172db06331 |
15 | c33645541 |
hex | 749feeba7 |
31306214311 has 16 divisors (see below), whose sum is σ = 32451328000. Its totient is φ = 30169830240.
The previous prime is 31306214297. The next prime is 31306214327. The reversal of 31306214311 is 11341260313.
It is a cyclic number.
It is not a de Polignac number, because 31306214311 - 217 = 31306083239 is a prime.
It is a super-2 number, since 2×313062143112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31306217311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8945440 + ... + 8948938.
It is an arithmetic number, because the mean of its divisors is an integer number (2028208000).
Almost surely, 231306214311 is an apocalyptic number.
31306214311 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
31306214311 is a deficient number, since it is larger than the sum of its proper divisors (1145113689).
31306214311 is a wasteful number, since it uses less digits than its factorization.
31306214311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4654.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 31306214311 its reverse (11341260313), we get a palindrome (42647474624).
The spelling of 31306214311 in words is "thirty-one billion, three hundred six million, two hundred fourteen thousand, three hundred eleven".
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