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31310030113 is a prime number
BaseRepresentation
bin11101001010001110…
…010010010100100001
32222211001100022211221
4131022032102110201
51003110331430423
622214510335041
72155614602425
oct351216222441
988731308757
1031310030113
111230777204a
1260997ba481
132c4c90254b
14173041ab85
15c33b4ae5d
hex74a392521

31310030113 has 2 divisors, whose sum is σ = 31310030114. Its totient is φ = 31310030112.

The previous prime is 31310030107. The next prime is 31310030131. The reversal of 31310030113 is 31103001313.

Together with next prime (31310030131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28207874304 + 3102155809 = 167952^2 + 55697^2 .

It is a cyclic number.

It is not a de Polignac number, because 31310030113 - 213 = 31310021921 is a prime.

It is not a weakly prime, because it can be changed into another prime (31310030413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15655015056 + 15655015057.

It is an arithmetic number, because the mean of its divisors is an integer number (15655015057).

Almost surely, 231310030113 is an apocalyptic number.

It is an amenable number.

31310030113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31310030113 is an equidigital number, since it uses as much as digits as its factorization.

31310030113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 31310030113 its reverse (31103001313), we get a palindrome (62413031426).

The spelling of 31310030113 in words is "thirty-one billion, three hundred ten million, thirty thousand, one hundred thirteen".