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313103434101113 is a prime number
BaseRepresentation
bin100011100110001000001001…
…0111101111011000101111001
31112001121101200122221212111102
41013030100102331323011321
5312014341313112213423
63025525422032341145
7122643655656553535
oct10714202275730571
91461541618855442
10313103434101113
1190845469a62307
122b1496626a47b5
13105926b11a5356
145746403a04bc5
15262e813971c28
hex11cc412f7b179

313103434101113 has 2 divisors, whose sum is σ = 313103434101114. Its totient is φ = 313103434101112.

The previous prime is 313103434101071. The next prime is 313103434101181. The reversal of 313103434101113 is 311101434301313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 312818932409344 + 284501691769 = 17686688^2 + 533387^2 .

It is a cyclic number.

It is not a de Polignac number, because 313103434101113 - 220 = 313103433052537 is a prime.

It is a super-2 number, since 2×3131034341011132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (313103434101613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156551717050556 + 156551717050557.

It is an arithmetic number, because the mean of its divisors is an integer number (156551717050557).

Almost surely, 2313103434101113 is an apocalyptic number.

It is an amenable number.

313103434101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

313103434101113 is an equidigital number, since it uses as much as digits as its factorization.

313103434101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 313103434101113 its reverse (311101434301313), we get a palindrome (624204868402426).

The spelling of 313103434101113 in words is "three hundred thirteen trillion, one hundred three billion, four hundred thirty-four million, one hundred one thousand, one hundred thirteen".