Base | Representation |
---|---|
bin | 100011100110001000001001… |
… | …1010101001110110111101001 |
3 | 1112001121101201002110022021120 |
4 | 1013030100103111032313221 |
5 | 312014341321143231213 |
6 | 3025525422411325453 |
7 | 122643656062523064 |
oct | 10714202325166751 |
9 | 1461541632408246 |
10 | 313103440211433 |
11 | 90845472456063 |
12 | 2b149664750889 |
13 | 105926b2534621 |
14 | 57464047558db |
15 | 262e81427c423 |
hex | 11cc41354ede9 |
313103440211433 has 32 divisors (see below), whose sum is σ = 444315152445696. Its totient is φ = 195683925685248.
The previous prime is 313103440211423. The next prime is 313103440211489. The reversal of 313103440211433 is 334112044301313.
It is not a de Polignac number, because 313103440211433 - 210 = 313103440210409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 313103440211394 and 313103440211403.
It is not an unprimeable number, because it can be changed into a prime (313103440211423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 42260460 + ... + 49113677.
It is an arithmetic number, because the mean of its divisors is an integer number (13884848513928).
Almost surely, 2313103440211433 is an apocalyptic number.
It is an amenable number.
313103440211433 is a deficient number, since it is larger than the sum of its proper divisors (131211712234263).
313103440211433 is a wasteful number, since it uses less digits than its factorization.
313103440211433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91375153.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 313103440211433 its reverse (334112044301313), we get a palindrome (647215484512746).
The spelling of 313103440211433 in words is "three hundred thirteen trillion, one hundred three billion, four hundred forty million, two hundred eleven thousand, four hundred thirty-three".
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