Base | Representation |
---|---|
bin | 101101100100000000101… |
… | …010111000110000011011 |
3 | 102002022202201122222211202 |
4 | 231210000222320300123 |
5 | 402244333323320212 |
6 | 10354214144544415 |
7 | 442132102201232 |
oct | 55440052706033 |
9 | 12068681588752 |
10 | 3131042401307 |
11 | aa795a89a397 |
12 | 42699792210b |
13 | 199343669432 |
14 | ab7869c9b19 |
15 | 566a3d620c2 |
hex | 2d900ab8c1b |
3131042401307 has 2 divisors, whose sum is σ = 3131042401308. Its totient is φ = 3131042401306.
The previous prime is 3131042401301. The next prime is 3131042401363. The reversal of 3131042401307 is 7031042401313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3131042401307 - 212 = 3131042397211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3131042401307.
It is not a weakly prime, because it can be changed into another prime (3131042401301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565521200653 + 1565521200654.
It is an arithmetic number, because the mean of its divisors is an integer number (1565521200654).
Almost surely, 23131042401307 is an apocalyptic number.
3131042401307 is a deficient number, since it is larger than the sum of its proper divisors (1).
3131042401307 is an equidigital number, since it uses as much as digits as its factorization.
3131042401307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 3131042401307 in words is "three trillion, one hundred thirty-one billion, forty-two million, four hundred one thousand, three hundred seven".
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