Base | Representation |
---|---|
bin | 100011100110001000100111… |
… | …1110001101110101111000011 |
3 | 1112001121111022202200002202222 |
4 | 1013030101033301232233003 |
5 | 312014400410301034242 |
6 | 3025530111155201255 |
7 | 122644023155334101 |
oct | 10714211761565703 |
9 | 1461544282602688 |
10 | 313104454314947 |
11 | 90845942932039 |
12 | 2b1498a82a622b |
13 | 1059281466c089 |
14 | 574649d2d4c71 |
15 | 262e8732e75d2 |
hex | 11cc44fc6ebc3 |
313104454314947 has 2 divisors, whose sum is σ = 313104454314948. Its totient is φ = 313104454314946.
The previous prime is 313104454314941. The next prime is 313104454315139. The reversal of 313104454314947 is 749413454401313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313104454314947 - 210 = 313104454313923 is a prime.
It is a super-2 number, since 2×3131044543149472 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (313104454314941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156552227157473 + 156552227157474.
It is an arithmetic number, because the mean of its divisors is an integer number (156552227157474).
Almost surely, 2313104454314947 is an apocalyptic number.
313104454314947 is a deficient number, since it is larger than the sum of its proper divisors (1).
313104454314947 is an equidigital number, since it uses as much as digits as its factorization.
313104454314947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 53.
The spelling of 313104454314947 in words is "three hundred thirteen trillion, one hundred four billion, four hundred fifty-four million, three hundred fourteen thousand, nine hundred forty-seven".
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