Base | Representation |
---|---|
bin | 101101100100000100111… |
… | …000001101010010000001 |
3 | 102002022221122111212221102 |
4 | 231210010320031102001 |
5 | 402300004412031423 |
6 | 10354225150104145 |
7 | 442133620246415 |
oct | 55440470152201 |
9 | 12068848455842 |
10 | 3131113002113 |
11 | aa7996730868 |
12 | 4269b74ab055 |
13 | 199355188565 |
14 | ab792126d45 |
15 | 566aa15ac28 |
hex | 2d904e0d481 |
3131113002113 has 2 divisors, whose sum is σ = 3131113002114. Its totient is φ = 3131113002112.
The previous prime is 3131113002079. The next prime is 3131113002151. The reversal of 3131113002113 is 3112003111313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3093859369969 + 37253632144 = 1758937^2 + 193012^2 .
It is a cyclic number.
It is not a de Polignac number, because 3131113002113 - 212 = 3131112998017 is a prime.
It is not a weakly prime, because it can be changed into another prime (3131113002163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565556501056 + 1565556501057.
It is an arithmetic number, because the mean of its divisors is an integer number (1565556501057).
Almost surely, 23131113002113 is an apocalyptic number.
It is an amenable number.
3131113002113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3131113002113 is an equidigital number, since it uses as much as digits as its factorization.
3131113002113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 3131113002113 its reverse (3112003111313), we get a palindrome (6243116113426).
The spelling of 3131113002113 in words is "three trillion, one hundred thirty-one billion, one hundred thirteen million, two thousand, one hundred thirteen".
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