Base | Representation |
---|---|
bin | 100011100110001101001011… |
… | …0100001010100110001101001 |
3 | 1112001122102120010110211102011 |
4 | 1013030122112201110301221 |
5 | 312020030421132144431 |
6 | 3025534405250235521 |
7 | 122644520353032511 |
oct | 10714322641246151 |
9 | 1461572503424364 |
10 | 313114231131241 |
11 | 90849aaa669901 |
12 | 2b14b776585ba1 |
13 | 10593712045987 |
14 | 5746b4995c841 |
15 | 262ec467bbcb1 |
hex | 11cc696854c69 |
313114231131241 has 2 divisors, whose sum is σ = 313114231131242. Its totient is φ = 313114231131240.
The previous prime is 313114231131181. The next prime is 313114231131269. The reversal of 313114231131241 is 142131132411313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 238319339384025 + 74794891747216 = 15437595^2 + 8648404^2 .
It is a cyclic number.
It is not a de Polignac number, because 313114231131241 - 213 = 313114231123049 is a prime.
It is not a weakly prime, because it can be changed into another prime (313114231131041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156557115565620 + 156557115565621.
It is an arithmetic number, because the mean of its divisors is an integer number (156557115565621).
Almost surely, 2313114231131241 is an apocalyptic number.
It is an amenable number.
313114231131241 is a deficient number, since it is larger than the sum of its proper divisors (1).
313114231131241 is an equidigital number, since it uses as much as digits as its factorization.
313114231131241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 31.
Adding to 313114231131241 its reverse (142131132411313), we get a palindrome (455245363542554).
The spelling of 313114231131241 in words is "three hundred thirteen trillion, one hundred fourteen billion, two hundred thirty-one million, one hundred thirty-one thousand, two hundred forty-one".
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