Base | Representation |
---|---|
bin | 100011100110010001111000… |
… | …1010100001000011100010011 |
3 | 1112001200101122221020202122222 |
4 | 1013030203301110020130103 |
5 | 312020212124122142344 |
6 | 3025543200555251255 |
7 | 122645326103606114 |
oct | 10714436124103423 |
9 | 1461611587222588 |
10 | 313124344334099 |
11 | 9085331a2728a1 |
12 | 2b151719449b2b |
13 | 1059466431a28c |
14 | 5747428b4c20b |
15 | 263013958b5ee |
hex | 11cc8f1508713 |
313124344334099 has 2 divisors, whose sum is σ = 313124344334100. Its totient is φ = 313124344334098.
The previous prime is 313124344334089. The next prime is 313124344334117. The reversal of 313124344334099 is 990433443421313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313124344334099 - 248 = 31649367623443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 313124344334099.
It is not a weakly prime, because it can be changed into another prime (313124344334089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156562172167049 + 156562172167050.
It is an arithmetic number, because the mean of its divisors is an integer number (156562172167050).
Almost surely, 2313124344334099 is an apocalyptic number.
313124344334099 is a deficient number, since it is larger than the sum of its proper divisors (1).
313124344334099 is an equidigital number, since it uses as much as digits as its factorization.
313124344334099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10077696, while the sum is 53.
The spelling of 313124344334099 in words is "three hundred thirteen trillion, one hundred twenty-four billion, three hundred forty-four million, three hundred thirty-four thousand, ninety-nine".
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