Base | Representation |
---|---|
bin | 1110001111010011111101… |
… | …11011100011110010111011 |
3 | 11002212102212212020002220012 |
4 | 13013221332323203302323 |
5 | 13101010334412131141 |
6 | 150332423055252135 |
7 | 6411151324052255 |
oct | 707517673436273 |
9 | 132772785202805 |
10 | 31312441130171 |
11 | 9a82593782503 |
12 | 361868921a04b |
13 | 146199abb0876 |
14 | 7a375cd82cd5 |
15 | 394796059ceb |
hex | 1c7a7eee3cbb |
31312441130171 has 2 divisors, whose sum is σ = 31312441130172. Its totient is φ = 31312441130170.
The previous prime is 31312441130167. The next prime is 31312441130221. The reversal of 31312441130171 is 17103114421313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31312441130171 - 22 = 31312441130167 is a prime.
It is not a weakly prime, because it can be changed into another prime (31312441130161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656220565085 + 15656220565086.
It is an arithmetic number, because the mean of its divisors is an integer number (15656220565086).
Almost surely, 231312441130171 is an apocalyptic number.
31312441130171 is a deficient number, since it is larger than the sum of its proper divisors (1).
31312441130171 is an equidigital number, since it uses as much as digits as its factorization.
31312441130171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 31312441130171 its reverse (17103114421313), we get a palindrome (48415555551484).
The spelling of 31312441130171 in words is "thirty-one trillion, three hundred twelve billion, four hundred forty-one million, one hundred thirty thousand, one hundred seventy-one".
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