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313133614042 = 2156566807021
BaseRepresentation
bin1001000111010000011…
…01111100001111011010
31002221020211010202012211
410203220031330033122
520112244201122132
6355503540025334
731423512542314
oct4435015741732
91087224122184
10313133614042
11110887841987
125082b99224a
13236b3ab3072
141122752c7b4
15822a705147
hex48e837c3da

313133614042 has 4 divisors (see below), whose sum is σ = 469700421066. Its totient is φ = 156566807020.

The previous prime is 313133614037. The next prime is 313133614043. The reversal of 313133614042 is 240416331313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 246642350161 + 66491263881 = 496631^2 + 257859^2 .

It is a junction number, because it is equal to n+sod(n) for n = 313133613995 and 313133614013.

It is not an unprimeable number, because it can be changed into a prime (313133614043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78283403509 + ... + 78283403512.

Almost surely, 2313133614042 is an apocalyptic number.

313133614042 is a deficient number, since it is larger than the sum of its proper divisors (156566807024).

313133614042 is a wasteful number, since it uses less digits than its factorization.

313133614042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156566807023.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 313133614042 its reverse (240416331313), we get a palindrome (553549945355).

The spelling of 313133614042 in words is "three hundred thirteen billion, one hundred thirty-three million, six hundred fourteen thousand, forty-two".

Divisors: 1 2 156566807021 313133614042