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31321444281241 is a prime number
BaseRepresentation
bin1110001111100100101111…
…00011110110101110011001
311002220022010022020120100211
413013302113203312232121
513101132304213444431
6150340512312131121
76411620405426152
oct707622743665631
9132808108216324
1031321444281241
119a86393826124
12361a380396aa1
1314627a41c51aa
147a3d74978929
15394b2165a2b1
hex1c7c978f6b99

31321444281241 has 2 divisors, whose sum is σ = 31321444281242. Its totient is φ = 31321444281240.

The previous prime is 31321444281199. The next prime is 31321444281247. The reversal of 31321444281241 is 14218244412313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28037067360016 + 3284376921225 = 5295004^2 + 1812285^2 .

It is a cyclic number.

It is not a de Polignac number, because 31321444281241 - 229 = 31320907410329 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31321444281194 and 31321444281203.

It is not a weakly prime, because it can be changed into another prime (31321444281247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15660722140620 + 15660722140621.

It is an arithmetic number, because the mean of its divisors is an integer number (15660722140621).

Almost surely, 231321444281241 is an apocalyptic number.

It is an amenable number.

31321444281241 is a deficient number, since it is larger than the sum of its proper divisors (1).

31321444281241 is an equidigital number, since it uses as much as digits as its factorization.

31321444281241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 147456, while the sum is 40.

Adding to 31321444281241 its reverse (14218244412313), we get a palindrome (45539688693554).

The spelling of 31321444281241 in words is "thirty-one trillion, three hundred twenty-one billion, four hundred forty-four million, two hundred eighty-one thousand, two hundred forty-one".