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31324012433 = 74474858919
BaseRepresentation
bin11101001011000011…
…100111111110010001
32222212000122200222122
4131023003213332101
51003122421344213
622220130144025
72156144466260
oct351303477621
988760580878
1031324012433
111231465218a
1260a2422015
132c527898cc
14173221a5d7
15c34eadd08
hex74b0e7f91

31324012433 has 4 divisors (see below), whose sum is σ = 35798871360. Its totient is φ = 26849153508.

The previous prime is 31324012381. The next prime is 31324012477. The reversal of 31324012433 is 33421042313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31324012433 - 224 = 31307235217 is a prime.

It is not an unprimeable number, because it can be changed into a prime (31324017433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237429453 + ... + 2237429466.

It is an arithmetic number, because the mean of its divisors is an integer number (8949717840).

Almost surely, 231324012433 is an apocalyptic number.

It is an amenable number.

31324012433 is a deficient number, since it is larger than the sum of its proper divisors (4474858927).

31324012433 is an equidigital number, since it uses as much as digits as its factorization.

31324012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4474858926.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 31324012433 its reverse (33421042313), we get a palindrome (64745054746).

The spelling of 31324012433 in words is "thirty-one billion, three hundred twenty-four million, twelve thousand, four hundred thirty-three".

Divisors: 1 7 4474858919 31324012433