Base | Representation |
---|---|
bin | 100011100111100110000110… |
… | …1001111010000000010100011 |
3 | 1112002022200111011210211020222 |
4 | 1013033030031033100002203 |
5 | 312031143023032133404 |
6 | 3030202231134553255 |
7 | 122664360650635664 |
oct | 10717141517200243 |
9 | 1462280434724228 |
10 | 313305201442979 |
11 | 90912a98401619 |
12 | 2b18079206882b |
13 | 105a87276bb735 |
14 | 57520a46db36b |
15 | 2634bc214cdbe |
hex | 11cf30d3d00a3 |
313305201442979 has 2 divisors, whose sum is σ = 313305201442980. Its totient is φ = 313305201442978.
The previous prime is 313305201442949. The next prime is 313305201443057. The reversal of 313305201442979 is 979244102503313.
It is a weak prime.
It is an emirp because it is prime and its reverse (979244102503313) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313305201442979 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 313305201442979.
It is not a weakly prime, because it can be changed into another prime (313305201442949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156652600721489 + 156652600721490.
It is an arithmetic number, because the mean of its divisors is an integer number (156652600721490).
Almost surely, 2313305201442979 is an apocalyptic number.
313305201442979 is a deficient number, since it is larger than the sum of its proper divisors (1).
313305201442979 is an equidigital number, since it uses as much as digits as its factorization.
313305201442979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4898880, while the sum is 53.
The spelling of 313305201442979 in words is "three hundred thirteen trillion, three hundred five billion, two hundred one million, four hundred forty-two thousand, nine hundred seventy-nine".
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