313310021214433 has 4 divisors (see below), whose sum is σ = 313317403157808. Its totient is φ = 313302639271060.

The previous prime is 313310021214427. The next prime is 313310021214457. The reversal of 313310021214433 is 334412120013313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 313310021214433 - 2²¹ = 313310019117281 is a prime.

It is a super-2 number, since 2×313310021214433² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313310021214395 and 313310021214404.

It is not an unprimeable number, because it can be changed into a prime (313310024214433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3690908023 + ... + 3690992908.

It is an arithmetic number, because the mean of its divisors is an integer number (78329350789452).

Almost surely, 2^{313310021214433} is an apocalyptic number.

It is an amenable number.

313310021214433 is a deficient number, since it is larger than the sum of its proper divisors (7381943375).

313310021214433 is an equidigital number, since it uses as much as digits as its factorization.

313310021214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7381943374.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 313310021214433 its reverse (334412120013313), we get a palindrome (647722141227746).

The spelling of 313310021214433 in words is "three hundred thirteen trillion, three hundred ten billion, twenty-one million, two hundred fourteen thousand, four hundred thirty-three".