Base | Representation |
---|---|
bin | 101101100101111011100… |
… | …100001100001011101001 |
3 | 102002112002102101102111221 |
4 | 231211323210030023221 |
5 | 402313044141242213 |
6 | 10355154521222041 |
7 | 442234146441613 |
oct | 55457344141351 |
9 | 12075072342457 |
10 | 3133104243433 |
11 | aa881873594a |
12 | 427272331921 |
13 | 1995b1887068 |
14 | ab900781db3 |
15 | 56774d8d38d |
hex | 2d97b90c2e9 |
3133104243433 has 2 divisors, whose sum is σ = 3133104243434. Its totient is φ = 3133104243432.
The previous prime is 3133104243419. The next prime is 3133104243473. The reversal of 3133104243433 is 3343424013313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2615326136809 + 517778106624 = 1617197^2 + 719568^2 .
It is a cyclic number.
It is not a de Polignac number, because 3133104243433 - 29 = 3133104242921 is a prime.
It is not a weakly prime, because it can be changed into another prime (3133104243413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1566552121716 + 1566552121717.
It is an arithmetic number, because the mean of its divisors is an integer number (1566552121717).
Almost surely, 23133104243433 is an apocalyptic number.
It is an amenable number.
3133104243433 is a deficient number, since it is larger than the sum of its proper divisors (1).
3133104243433 is an equidigital number, since it uses as much as digits as its factorization.
3133104243433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 34.
Adding to 3133104243433 its reverse (3343424013313), we get a palindrome (6476528256746).
The spelling of 3133104243433 in words is "three trillion, one hundred thirty-three billion, one hundred four million, two hundred forty-three thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •