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313312132200497 is a prime number
BaseRepresentation
bin100011100111101001010101…
…0010101111111100000110001
31112002100100101012020210012212
41013033102222111333200301
5312031301221320403442
63030205335001101505
7122665024466255063
oct10717225225774061
91462310335223185
10313312132200497
1190915a246622a1
122b181ba7187895
13105a929055c8a1
145752560d91733
152634e7a83aa82
hex11cf4aa57f831

313312132200497 has 2 divisors, whose sum is σ = 313312132200498. Its totient is φ = 313312132200496.

The previous prime is 313312132200443. The next prime is 313312132200511. The reversal of 313312132200497 is 794002231213313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 249410510365696 + 63901621834801 = 15792736^2 + 7993849^2 .

It is an emirp because it is prime and its reverse (794002231213313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313312132200497 - 214 = 313312132184113 is a prime.

It is not a weakly prime, because it can be changed into another prime (313312132200437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156656066100248 + 156656066100249.

It is an arithmetic number, because the mean of its divisors is an integer number (156656066100249).

Almost surely, 2313312132200497 is an apocalyptic number.

It is an amenable number.

313312132200497 is a deficient number, since it is larger than the sum of its proper divisors (1).

313312132200497 is an equidigital number, since it uses as much as digits as its factorization.

313312132200497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 163296, while the sum is 41.

The spelling of 313312132200497 in words is "three hundred thirteen trillion, three hundred twelve billion, one hundred thirty-two million, two hundred thousand, four hundred ninety-seven".