Base | Representation |
---|---|
bin | 100011100111101001010101… |
… | …0011001110110010100001011 |
3 | 1112002100100101021011010220211 |
4 | 1013033102222121312110023 |
5 | 312031301222100231103 |
6 | 3030205335034501551 |
7 | 122665024510665244 |
oct | 10717225231662413 |
9 | 1462310337133824 |
10 | 313312133211403 |
11 | 90915a25192857 |
12 | 2b181ba75948b7 |
13 | 105a9290824a61 |
14 | 5752561175ccb |
15 | 2634e7a98a36d |
hex | 11cf4aa67650b |
313312133211403 has 4 divisors (see below), whose sum is σ = 313342037978320. Its totient is φ = 313282228444488.
The previous prime is 313312133211373. The next prime is 313312133211409. The reversal of 313312133211403 is 304112331213313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313312133211403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (313312133211409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14952367743 + ... + 14952388696.
It is an arithmetic number, because the mean of its divisors is an integer number (78335509494580).
Almost surely, 2313312133211403 is an apocalyptic number.
313312133211403 is a deficient number, since it is larger than the sum of its proper divisors (29904766917).
313312133211403 is a wasteful number, since it uses less digits than its factorization.
313312133211403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29904766916.
The product of its (nonzero) digits is 11664, while the sum is 31.
Adding to 313312133211403 its reverse (304112331213313), we get a palindrome (617424464424716).
The spelling of 313312133211403 in words is "three hundred thirteen trillion, three hundred twelve billion, one hundred thirty-three million, two hundred eleven thousand, four hundred three".
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