Base | Representation |
---|---|
bin | 101101100110110111100… |
… | …001010010001000000011 |
3 | 102002121200112002221221202 |
4 | 231212313201102020003 |
5 | 402322124142124212 |
6 | 10355442412411415 |
7 | 442301112264014 |
oct | 55466741221003 |
9 | 12077615087852 |
10 | 3134110114307 |
11 | aa91944a9597 |
12 | 4274b3176b6b |
13 | 19971209b523 |
14 | ab9981bb00b |
15 | 567d332e0c2 |
hex | 2d9b7852203 |
3134110114307 has 2 divisors, whose sum is σ = 3134110114308. Its totient is φ = 3134110114306.
The previous prime is 3134110114241. The next prime is 3134110114321. The reversal of 3134110114307 is 7034110114313.
It is a strong prime.
It is an emirp because it is prime and its reverse (7034110114313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3134110114307 - 212 = 3134110110211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3134110114307.
It is not a weakly prime, because it can be changed into another prime (3134110164307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567055057153 + 1567055057154.
It is an arithmetic number, because the mean of its divisors is an integer number (1567055057154).
Almost surely, 23134110114307 is an apocalyptic number.
3134110114307 is a deficient number, since it is larger than the sum of its proper divisors (1).
3134110114307 is an equidigital number, since it uses as much as digits as its factorization.
3134110114307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 29.
The spelling of 3134110114307 in words is "three trillion, one hundred thirty-four billion, one hundred ten million, one hundred fourteen thousand, three hundred seven".
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