3134204424433 has 8 divisors (see below), whose sum is σ = 3173982048000. Its totient is φ = 3094429404768.

The previous prime is 3134204424367. The next prime is 3134204424469. The reversal of 3134204424433 is 3344244024313.

3134204424433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3134204424433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3134204424392 and 3134204424401.

It is not an unprimeable number, because it can be changed into a prime (3134204421433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1831293 + ... + 3101941.

It is an arithmetic number, because the mean of its divisors is an integer number (396747756000).

Almost surely, 2^{3134204424433} is an apocalyptic number.

It is an amenable number.

3134204424433 is a deficient number, since it is larger than the sum of its proper divisors (39777623567).

3134204424433 is a wasteful number, since it uses less digits than its factorization.

3134204424433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1301951.

The product of its (nonzero) digits is 331776, while the sum is 37.

Adding to 3134204424433 its reverse (3344244024313), we get a palindrome (6478448448746).

The spelling of 3134204424433 in words is "three trillion, one hundred thirty-four billion, two hundred four million, four hundred twenty-four thousand, four hundred thirty-three".